Question

usando a Razão trigonométricas calcule o valor de X em cada caso.​

Answer 1

a)

$\sin(30) = \frac{x}{12} \\ \frac{1}{2} = \frac{x}{12} \\ x =12. \frac{1}{2} \\ x = 6$

b)

$\sin(45) = \frac{3 \sqrt{2} }{x} \\ \frac{ \sqrt{2} }{2} = \frac{3 \sqrt{2} }{x} \\ x = 2.3 \\ x = 6$

c)

$\tan(60) = \frac{6 \sqrt{3} }{x} \\ \sqrt{3} = \frac{6 \sqrt{3} }{x} \\ x = 6$

d)

$\cos(30) = \frac{5 \sqrt{3} }{x} \\ \frac{ \sqrt{3} }{2} = \frac{5 \sqrt{3} }{x} \\ x = 2.5 \\ x = 10$

Espero ter ajudado bons estudos :)

Answer 2

A) Sen30=x/12

  1/2=x/12

x=12/2=6

B) Sen45=3√2/x

   √2/2=3√2/x

     x=3√2.2/√2=6

C) tg60=6√3/x

      √3=6√3/x

      x=6√3/√3=6

D) Cos30=5√3/x

     √3/2=5√3/x

       x=5√3.2/√3=10