Question

Usando a lei dos senos, determine a medida x na figura abaixo​

Answer 1

Explicação passo-a-passo:

$\frac{40}{sen60^{0}}=\frac{x}{sen45^{0}}$

$\frac{40}{\frac{\sqrt{3}}{2}}=\frac{x}{\frac{\sqrt{2}}{2}}$

$\frac{80}{\sqrt{3}}=\frac{2x}{\sqrt{2}}$

$80.\sqrt{2}=2x.\sqrt{3}$

$x=\frac{80.\sqrt{2}}{2.\sqrt{3}}=\frac{40.\sqrt{2}}{\sqrt{3}}$

$x=\frac{40\sqrt{2}.\sqrt{3}}{\sqrt{3}.\sqrt{3}}$

$x=\frac{40\sqrt{6}}{3}m$