Question

Usando a fórmula de Bhaskara

Responda:

x²-8x+12=0

Answer 1

x² - 8x + 12 = 0


delta = b² - 4.a.c


a= 1
b= -8
c= 12


delta = (-8)² - 4.1.12
delta = 64 - 48
delta = 16


x = -b ± √delta/2.a

x = -(-8) ± √16/2.1

x = 8 ± 4/2

x = 8 + 4/2 = 12/2 = 6

x = 8 - 4/2 = 4/2 = 2


s={ 6, 2 }




☆Espero ter ajudado!