Question

Usando a fórmula de Bháskara, resolve a equação ? Me ajudem

Answer 1

Resposta:

A

Explicação passo-a-passo:

$2x^2+5x-3=0$

$\Delta=5^2-4\cdot2\cdot(-3)$

$\Delta=25+24$

$\Delta=49$

$x=\dfrac{-5\pm\sqrt{49}}{2\cdot2}=\dfrac{-5\pm7}{4}$

$x'=\dfrac{-5+7}{4}~\longrightarrow~x'=\dfrac{2}{4}~\longrightarrow~x'=\dfrac{1}{2}$

$x"=\dfrac{-5-7}{4}~\longrightarrow~x"=\dfrac{-12}{4}~\longrightarrow~x"=-3$

Letra A