Question

usando a formula de bhaskara  resolva a equação (x+5)²=7 ?

Answer 1

$(x+5)^2=7\\ x^2-10x+25-7=0\\ \\ x^2-10x+18=0\\ \\ \Delta=(-10)^2-4.1.18=100-72=28\\ \\ \boxed{x=\frac{10 \pm \sqrt{28}}{2}=5\pm\sqrt7}$