Question

Usando a formula de bhaskara,como resolveria essa equação : 4x²+32x+64=4

Answer 1

b²-4.a.c
32²-4.4.64
1024-1024
0

-b+-√delta/2.a

-32+-0/8

x1 = -32+0/8
x1 = -4

x2 = -32-0/8
x2 = -4

Answer 2

4x² + 32x + 64 = 4
4x² + 32x + 64 - 4 = 0
4x² + 32x + 60 = 0

a=4 b=32 c=60 

Δ = 32² -4(4)(60)
Δ = 1024 - 960
Δ = 64

x₁ = $\frac{-32 + \sqrt{64} }{2(4)}$ = -3
x₂ = $\frac{-32 - \sqrt{64} }{2(4)}$ = -5