Question

usando a Fórmula de Bhaskara
1°: Y=x²-4x+3

2°: f(x)=-x²-3x-2

3°: y= 2x²-8x+8

Answer 1

1) y=x^2-4x+3
x^2-4x+3=0
delta=b^2-4.a.c
delta=(-4)^2-4.1.3
delta=16-12
delta=4
x=-b-/+ raiz de delta/2a
x=-(-4)-2/2.1
x=4-2/2
x=2/2
x=1
x=-(-4)+2/2.1
x=4+2/2
x=6/2
x=3
2) f(x)=-x^2-3x-2
-x^2-3x-2=0
delta=b^2-4.a.c
delta=(-3)^2-4.(-1).(-2)
delta=9-8
delta=1
x=-b-/+ raiz de delta/2a
x=-(-3)-1/2.(-1)
x=3-1/-2
x=2/-2
x=-1
x=-(-3)+1/2.(-1)
x=3+1/-2
x=4/-2
x=-2
3) y=2x^2-8x+8
2x^2-8x+8=0
delta=b^2-4.a.c
delta=(-8)^2-4.2.8
delta=64-64
delta=0
x=-b-/+ raiz de delta/2a
x=-(-8)-0/2.2
x=8-0/4
x=8/4
x=2