Question

Usando a definição calcule:
a)log2 16
b)log3 27
c)log5 25
d)log 0,001
e)log1/4 4

Answer 1

a) log2 16 = x
2^x = 16
2^x = 2⁴ ==> x = 4

b) log3 27 = x
3^x = 27
3^x = 3³ ==> x = 3

c) log5 25 = x
5^x = 25
5^x = 5² ==> x = 2

d) log0,001 = x
10^x = 0,001
10^x = 10^(-3) ==> x = - 3

e) log1/4 4= x
1/4^x = 4
4^(- x) = 4¹
-x = 1 ==> x = - 1