Question

urgenteeeee pooooor favooooooor​

Answer 1

(a)

$\dfrac{1}{7}=\dfrac{x-6}{49}\Rightarrow7(x-6)=49\Rightarrow7x-42=49\Rightarrow7x=49+42\\ \Rightarrow7x=91\Rightarrow x=13$

(b)

$\dfrac{5x+3}{10}=\dfrac{-21}{30}\Rightarrow30(5x+3)=-210\Rightarrow150x+90=-210\Rightarrow150x=-210-90\\\Rightarrow150x=-300\Rightarrow x=-2$