Question

urgenteee, me ajudem por favor
Simplificando a expressao (√3-√2)² -2(1-√6)-(√3-√2)(√3-√2) obtém-se : 2
preciso da resolucao de como chega nesse resultado

Answer 1

$(\sqrt{3}- \sqrt{2})^2 - 2(1- \sqrt{6} ) - ( \sqrt{3}- \sqrt{2})( \sqrt{3} - \sqrt{2} ) = \\ (\sqrt{3}- \sqrt{2})^2 - 2(1- \sqrt{6} ) - (\sqrt{3}- \sqrt{2})^2= \\ (\sqrt{3}- \sqrt{2})^2 - (\sqrt{3}- \sqrt{2})^2 - 2(1- \sqrt{6} )=- 2(1- \sqrt{6} ) \\= -2+2 \sqrt{6}$

*******************************************************************
$(\sqrt{3}+ \sqrt{2})^2 - 2(1- \sqrt{6} ) - ( \sqrt{3} + \sqrt{2})( \sqrt{3} - \sqrt{2} ) = \\ (\sqrt{3}+ \sqrt{2})^2 - 2(1- \sqrt{6} ) - ((\sqrt{3})^2- (\sqrt{2})^2)= \\ ( \sqrt{3})^2+ 2 \sqrt{3} \sqrt{2}+( \sqrt{2} )^2 -2+2 \sqrt{6}-3+2 = \\ 3+2 \sqrt{6}+2-2-2 \sqrt{6}-3+2 = 2 \sqrt{6}-2 \sqrt{6}+3+2-2-3+2 = 2$