Question

urgente! urgente! urgente! urgente! urgente!
Preciso urgente da resposta desse questão de logaritmo!!!

Answer 1

$\log_3\left(\dfrac{x-2}{2}\right)+\log_32-2\log_48=0\\\\\\\log_3\left(\dfrac{x-2}{2}\right)+\log_32-2\log_4(2\cdot4)=0\\\\\\\log_3\left(\dfrac{x-2}{2}\right)+\log_32-2(\log_4(2)+\log_4(4))=0\\\\\\\log_3\left(\dfrac{x-2}{2}\right)+\log_32-2\left(\dfrac12+1\right)=0\\\\\\\log_3\left(\dfrac{x-2}{2}\right)+\log_32-(1+2)=0\\\\\\\log_3\left(\dfrac{x-2}{2}\right)+\log_32-3=0\\\\\\\log_3\left(\dfrac{x-2}{2}\right)+\log_32-\log_327=0\\\\\\\log_3\left(\dfrac{x-2}{2}\right)+\log_3\left(\dfrac{2}{27}\right)=0$

$\log_3\left(\dfrac{x-2}{2}\right)=-\log_3\left(\dfrac{2}{27}\right)\\\\\\\log_3\left(\dfrac{x-2}{2}\right)=\log_3\left(\dfrac{27}{2}\right)\\\\\\\dfrac{x-2}{2}=\dfrac{27}{2}\\\\x-2=27\\\\x=29$