Question

URGENTE!!!!!!!!!!!

Resolva as adições com denominadores iguais e diferentes:
Obs: precisa aparecer as contas

a) 1/3+5/2
b)4/7+8/10
c)2/5+3/6
d)6/7+9/7
e)3/10+4/2
f)4/9+8/6​

Answer 1

a)2,83

b)1,37

c)0,09

d)2,14

e)2,03

f)infezlismente não consegui ajudar

desculpe se não ajudei....

Answer 2

Resposta:

$a)\ \dfrac{1}{3}+\dfrac{5}{2}=\boxed{\dfrac{17}{6}=2\dfrac{5}{6}}\\\\b)\ \dfrac{5}{7}+\dfrac{8}{10}=\boxed{\dfrac{48}{35}=1\dfrac{13}{35}}\\\\c)\ \dfrac{2}{5}+\dfrac{3}{6}=\boxed{\dfrac{27}{30}=\dfrac{9}{10}}\\\\d)\ \dfrac{6}{7}+\dfrac{9}{7}=\boxed{\dfrac{15}{7}=2\dfrac{1}{7}}\\\\e)\ \dfrac{3}{10}+\dfrac{4}{2}=\boxed{\dfrac{23}{10}=2\dfrac{3}{10}}\\\\f)\ \dfrac{4}{9}+\dfrac{8}{6}=\boxed{\dfrac{16}{9}=1\dfrac{7}{16}}$

Explicação passo-a-passo:

Para resolver essas adições, primeiro precisamos fazer o Mínimo Múltiplo Comum (MMC) entre os denominadores, então, vamos calculá-los:

a) MMC(2 , 3) = 6

2, 3 | 2

1, 3 | 3

1, 1  | 1

       ↓→ 2 × 3 × 1 = 6

b) MMC (7, 10) = 70

7, 10 | 2

7,  5 | 5

7,   1 | 7

1,    1 | 1

         ↓→ 2 × 5 × 7 × 1 = 70

c)  MMC(5, 6) = 30

5, 6 | 2

5, 3 | 3

5,  1 | 5

1,    1 | 1

         ↓→ 2 × 3 × 5 × 1 = 30

d) Os denominadores são iguais, então MMC (7, 7) = 7

e) MMC (2, 10) = 10

2, 10 | 2

1,   5 | 5

1,   1  | 1

        ↓→ 2 × 5 × 1 = 10

f) MMC (6,9) = 18

6, 9 | 2

3, 9 | 3

1,  3 | 3

1,   1 | 1

        ↓→ 2 × 3 × 3 × 1 = 18

Agora vamos aos cálculos

$a)\ MMC(2 , 3) = 6\\\\\dfrac{1}{3}+\dfrac{5}{2}=\dfrac{2\times1}{6}+\dfrac{3\times5}{6} =\dfrac{2+15}{6}=\dfrac{17}{\ 6}=\dfrac{12}{6}+\dfrac{5}{6}=2\dfrac{5}{6}\\\\b)\ MMC (7, 10) = 70\\\\\dfrac{4}{7}+\dfrac{8}{10}=\dfrac{10\times4}{70}+\dfrac{7\times8}{70}=\dfrac{40}{70}+\dfrac{56}{70}=\dfrac{96}{70}=\dfrac{48}{35}=\dfrac{35}{35}+\dfrac{13}{35}=1\dfrac{13}{35}$

$c)\ MMC(5, 6) = 30\\\\\dfrac{2}{5}+\dfrac{3}{6}=\dfrac{6\times2}{30}+\dfrac{5\times3}{30}=\dfrac{12+15}{30}=\dfrac{27}{30}=\dfrac{9}{10}\\\\d)\ MMC(7,7) = 7\\\\\dfrac{6}{7}+\dfrac{9}{7}=\dfrac{6+9}{7}=\dfrac{15}{7}=\dfrac{14}{7}+\dfrac{1}{7}=2\dfrac{1}{7}\\\\e)\ MMC (2, 10) = 10\\\\\dfrac{3}{10}+\dfrac{4}{2}=\dfrac{1\times3}{10}+\dfrac{5\times4}{10}=\dfrac{3+20}{10}=\dfrac{23}{10}=\dfrac{20}{10}+\dfrac{3}{10}=2\dfrac{3}{10}$

$f)\ MMC (6,9) = 18\\\\\dfrac{4}{9}+\dfrac{8}{6}=\dfrac{2\times4}{18}+\dfrac{3\times8}{18}=\dfrac{8+24}{18}=\dfrac{32}{18}=\dfrac{16}{9}=\dfrac{9}{9}+\dfrac{7}{9}=1\dfrac{7}{9}$

${\begin{center}\fbox{\rule{3ex}{2ex}\hspace{19.3ex}{#ESPERO TER AJUDADO !}\hspace{19.3ex}\rule{3ex}{2ex}}}{\end{center}}$

$\fbox{{\begin{minipage}[t]{0.89\textwidth{ }}\sc{Escolha\ a\ melhor\ resposta\ entre\ as\ obtidas\ e\ voc{\^{e}}\ receber{\'{a}}\ 25\%\ dos\ pontos\ que\ voc\^{e}\ gastou\ para\ a\ sua\ pergunta.}\end{minipage}{ }}}$