Question

**Urgente preciso pra entregar hoje**

Calcule o valor numérico da expressão algébrica a seguir

Answer 1

Explicação passo-a-passo:

$\sf 2x^3y^2+xy^2-6x+2y-1$

$\sf =2\cdot(-3)^3\cdot\left(\dfrac{2}{3}\right)^2+(-3)\cdot\left(\dfrac{2}{3}\right)^2-6\cdot(-3)+2\cdot\dfrac{2}{3}-1$

$\sf =2\cdot(-27)\cdot\dfrac{4}{9}+(-3)\cdot\dfrac{4}{9}+18+\dfrac{4}{3}-1$

$\sf =\dfrac{-216}{9}-\dfrac{12}{9}+18+\dfrac{4}{3}-1$

$\sf =-24-\dfrac{4}{3}+18+\dfrac{4}{3}-1$

$\sf =-24+18-1-\dfrac{4}{3}+\dfrac{4}{3}$

$\sf =-24+18-1$

$\sf =-6-1$

$\sf =\red{-7}$

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo-a-passo:

$\sf 2x^3y^2 + xy^2 - 6x + 2y - 1$

$\sf 2.(-3)^3.\left(\dfrac{2}{3}\right)^2 + (-3).\left(\dfrac{2}{3}\right)^2 - 6.(-3) + 2.\left(\dfrac{2}{3}\right) - 1$

$\sf 2.(-27).\left(\dfrac{4}{9}\right) + (-3).\left(\dfrac{4}{9}\right) - 6.(-3) + 2.\left(\dfrac{2}{3}\right) - 1$

$\sf 2.(-3).\left(\dfrac{4}{1}\right) - \left(\dfrac{4}{3}\right) - 6.(-3) + \left(\dfrac{4}{3}\right) - 1$

$\sf -\left(\dfrac{24}{1}\right) - \left(\dfrac{4}{3}\right) + 18 + \left(\dfrac{4}{3}\right) - 1$

$\sf -\left(\dfrac{24}{1}\right) + 18 + - 1$

$\sf -24 + 18 + - 1$

$\boxed{\boxed{\sf -7}}$