Question

URGENTE POR FAVOR

Usando a fórmula de Bhaskara, resolva em R a equação dada

X² + 3/ 10 - 5X + 3/15 = 3-2X/6 ​

Answer 1

Resposta passo-a-passo:

$x^2+\frac{3}{10} -5x +\frac{3}{15} =3-\frac{2x}{6}\\\\M.M.C: 10,\ 15\ e\ 6 = 30\\\\\frac{30x^2+9-150x+6}{30}= \frac{90-10x}{30} \\\\30x^2+9-150x+6=90-10x\\30x^2-150x+10x=90-9-6\\30x^2-140x=75\\30x^2-140x-75=0\\(30x^2-140x-75)/5=0 / 5\\\\6x^2-28x-15=0\\\ a=6\\b=-28\\c=-15\\\Delta=b^2-4*a*c\\\Delta=(-28)^2-4*6*(-15)\\\Delta=784+360\\\Delta=1144\\\\x=\frac{-b_-^+\sqrt{\Delta}}{2*a}$

$x=\frac{-(-28)_-^+\sqrt{1144} }{2*6} \\\\x'=\frac{28+2\sqrt{286}}{12}=>\frac{7+2\sqrt{286} }{3} \\\\x"= \frac{28-2\sqrt{286} }{12}=>\frac{7-2\sqrt{286} }{3}$