Question

Urgente, pergunta em anexo.

Answer 1

Montando a matriz M:

$M=\left[\begin{array}{ccc}m_{11}&m_{12}&m_{13}\\m_{21}&m_{22}&m_{23}\end{array}\right]\\M=\left[\begin{array}{ccc}1+2\times1&1+2\times2&1+2\times3\\2+2\times1&2+2\times2&2+2\times3\end{array}\right] \\M=\left[\begin{array}{ccc}3&5&7\\4&6&8\end{array}\right]$

Fazendo M=N:

$\left[\begin{array}{ccc}3&5&7\\4&6&8\end{array}\right]=\left[\begin{array}{ccc}r-s&5&t-2s\\4&t+3r&8\end{array}\right]$

Sistema linear:

$\left\{ \begin{array}{c}r-s=3\\t+3r=6\\t-2s=7\\\end{array}$

Resolvendo:

$r-s=3\\r=s+3\\\\t+3r=6\\t+3(s+3)=6\\t+3s+9=6\\t=6-9-3s\\t=-3-3s\\\\t-2s=7\\-3-3s-2s=7\\-5s=7+3\\s=-10/5\\s=-2\\\\t=-3-3s\\t=-3-3(-2)\\t=-3+6\\t=3\\\\r=s+3\\r=-2+3\\r=1$

Resposta:

r = 1

s = -2

t = 3