Question

URGENTE!!!

o valor de x na equação $\frac{9^{3X}}{3} = \frac{3}{\sqrt{3} }$

Answer 1

Resposta:

Explicação passo-a-passo:

$\frac{9^3^x}{3} =\frac{3}{\sqrt{3} }\\\\\frac{(3^2)^3^x}{3} =\frac{3}{3^\frac{1}{2} }\\\\\frac{3^6^x}{3} = \frac{3}{3^-^2}\\\\3^6^x^-^1 = 3^1^-^\frac{1}{2}\\\\6x -1= \frac{1}{2}\\\\6x = \frac{1}{2}+1\\\\6x = \frac{3}{2}\\\\x = \frac{3}{2}.\frac{1}{6} \\\\x = \frac{3}{12}=\frac{1}{4}$