Question

Urgente. Me ajudem!

Answer 1

Resposta:

AB= 16,37 cm

PQ= 6 cm

BM= 20,78 cm

Explicação passo-a-passo:

$cos30^\°}=\frac{QA}{12}=>0,866*12=QA=>QA=10,39cm\\\\sen30^\°}=\frac{PQ}{12}=>0,5*12=PQ=>PQ=6cm\\\\cos60^\°}=\frac{10,39}{BM}=>0,5BM=10,39=>BM=\frac{10,39}{0,5}=>BM=20,78cm$

$tag60^\°}=\frac{10,39}{BQ}=>1,732*BQ=10,39=>BQ=\frac{10,39}{1,732}=>BQ=5,998cm\\\\QA+QB=AB=>10,39+5,998=16,37=>AB=16,37cm$