Question

!!URGENTE!!
Encontre o valor para as incógnitas:
Com cálculos ​

Answer 1

Explicação passo-a-passo:

c)

• $\sf cos~60^{\circ}=\dfrac{32}{e}$

$\sf \dfrac{1}{2}=\dfrac{32}{e}$

$\sf e=2\cdot32$

$\sf e=64$

• $\sf tg~60^{\circ}=\dfrac{f}{32}$

$\sf \sqrt{3}=\dfrac{f}{32}$

$\sf f=32\sqrt{3}$

• $\sf sen~45^{\circ}=\dfrac{32}{g}$

$\sf \dfrac{\sqrt{2}}{2}=\dfrac{32}{g}$

$\sf \sqrt{2}\cdot g=2\cdot32$

$\sf \sqrt{2}\cdot g=64$

$\sf g=\dfrac{64}{\sqrt{2}}$

$\sf g=\dfrac{64}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}$

$\sf g=\dfrac{64\sqrt{2}}{2}$

$\sf g=32\sqrt{2}$

d)

• $\sf sen~60^{\circ}=\dfrac{10}{h}$

$\sf \dfrac{\sqrt{3}}{2}=\dfrac{10}{h}$

$\sf \sqrt{3}\cdot h=2\cdot10$

$\sf \sqrt{3}\cdot h=20$

$\sf h=\dfrac{20}{\sqrt{3}}$

$\sf h=\dfrac{20}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}$

$\sf h=\dfrac{20\sqrt{3}}{3}$

• $\sf tg~30^{\circ}=\dfrac{i}{10}$

$\sf \dfrac{\sqrt{3}}{3}=\dfrac{i}{10}$

$\sf 3i=10\sqrt{3}$

$\sf i=\dfrac{10\sqrt{3}}{3}$

• $\sf cos~30^{\circ}=\dfrac{10}{j}$

$\sf \dfrac{\sqrt{3}}{2}=\dfrac{10}{j}$

$\sf \sqrt{3}\cdot j=2\cdot10$

$\sf \sqrt{3}\cdot j=20$

$\sf j=\dfrac{20}{\sqrt{3}}$

$\sf j=\dfrac{20}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}$

$\sf j=\dfrac{20\sqrt{3}}{3}$