URGENTE
Determine o valor numérico da função F(x) = x/2 +1/3, para :
A) x=0
B) x=1
C) x= -2/3
Soluções para a tarefa
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A) x=0
F(x) = x/2 +1/3
F(x) = 0/2 +1/3
F(x) = 1/3
B) x=1
F(x) = x/2 +1/3
F(x) = 1/2 +1/3
F(x) = 3/6 +2/6
F(x) = 5/6
C) x= -2/3
F(x) = (-2/3)/2 +1/3
F(x) = (-2/3).(1/2) +1/3
F(x) = -2/6 +1/3
F(x) = -2/6 +2/6
F(x) = 0
F(x) = x/2 +1/3
F(x) = 0/2 +1/3
F(x) = 1/3
B) x=1
F(x) = x/2 +1/3
F(x) = 1/2 +1/3
F(x) = 3/6 +2/6
F(x) = 5/6
C) x= -2/3
F(x) = (-2/3)/2 +1/3
F(x) = (-2/3).(1/2) +1/3
F(x) = -2/6 +1/3
F(x) = -2/6 +2/6
F(x) = 0
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