Matemática, perguntado por Logizinho, 1 ano atrás

URGENTE!!
Dados log2= 0,301, log3= 0,477 e log7=0845, calcule.

A) Log ⁴√125

B) Log 25/6

C) Log 35

Soluções para a tarefa

Respondido por viniciushenrique406
1
Letra A)

\ell og(\sqrt[4]{125})~\Leftrightarrow~\ell og(\sqrt[4]{5^3})~\Leftrightarrow~\ell og(5^3)^{\frac{1}{4}}~\Leftrightarrow~\ell og(5)^{\frac{3}{4}}~\Leftrightarrow~ \frac{3}{4}\ell og(5)\\\\\frac{3}{4}\ell og(\frac{10}{2})~\Leftrightarrow~\frac{3}{4}(\ell og10-\ell og2)~\Leftrightarrow~\frac{3}{4}(1-0,301)~\Leftrightarrow~\frac{3}{4}(0,699)\\\\\dfrac{2,097}{4}~\Leftrightarrow~\fbox{$0,52425$}

Letra B)

\ell og(\frac{25}{6})~\Leftrightarrow~\ell og(25)-\ell og(6)~\Leftrightarrow~\ell og(5^2)-[\ell og(2\cdot3)]\\\\2\ell og(5)-[\ell og(2)+\ell og(3)]~\Leftrightarrow~2\ell og(\frac{10}{2})-[0,301+0,477]\\\\2\cdot[\ell og(10)-\ell og(2)]-[0,778]~\Leftrightarrow~2\cdot[1-0,301]-0.778\\\\2\cdot[0,699]-0,778~\Leftrightarrow~1,398-0,778~\Leftrightarrow~\fbox{$0,62$}

Letra C)

\ell og(35)~\Leftrightarrow~\ell og(7\cdot5)~\Leftrightarrow~\ell og(7)+\ell og(5)~\Leftrightarrow~0,845+\ell og(\frac{10}{2})\\\\0,845+[\ell og(10)-\ellog(2)]~\Leftrightarrow~0,845+[1-0,301]~\Leftrightarrow~0,845+0,699\\\\\fbox{$1,544$}

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