Question

"Urgente" ☺
Dada função defina por f 1(x)=2x+1
F(0),f(7),f(-2),f(-3)
F(x)=2x²-1
F(-1), f(-1/2=

Answer 1

f1(x) = 2 x + 1
___________

f(0)
-----
f1(x)= 2x + 1
f(0) = 2x + 1
f(0) = 2(0) +1
f(0) = 0 + 1
f(0) = 1

f(7)
-----
f1(x) = 2x + 1
f(7) = 2(7) + 1
f(7) = 14 + 1
f(7) = 15

f(-2)
------
f1(x) = 2 +1
f(-2) = 2(-2) + 1
f(-2) = -4 + 1
f(-2) = -3

f(-3)
------
f1(x) = 2x + 1
f(-3) = 2(-3) + 1
f(-3) = -6 + 1
f(-3) = -5

f(x) = 2x^2 - 1
_________

f(-1)
-----
f(x) = 2x^2 - 1
f(-1) = 2(-1)^2 - 1
f(-1) = 2(1) - 1
f(-1) = 2- 1
f(-1) = 1

f(-1/2)
--------
f(x) = 2x^2 - 1
f(-1/2) = 2(-1/2)^2 - 1
f(-1/2) = 2 (1/4) - 1
f(-1/2) = 2/4 - 1.(m.m.c=4)
f(-1/2) = 2 - 4 /4
f(-1/2) = -2/4 (÷2)
f(-1/2) = -1/2