Question

URGENTE! Calcule, preciso pra hoje por favor!

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Answer 1

Resposta:

desculpa não posso ajudar

Explicação passo-a-passo:

desculpa mesmo

Answer 2

Explicação passo-a-passo:

3)

a)

$\sqrt{49} + \sqrt{16} = 7 + 4 = 11$

b)

$\sqrt[3]{8} - \sqrt[4]{16} = 2 - 2 = 0$

c)

$- 5 \sqrt{9} + 2 \sqrt{169} = - 5.3 + 2.13 = - 15 + 26 = 11$

d)

$10 \sqrt[3]{2} + 4 \sqrt[3]{2} - \sqrt[3]{2} = 14 \sqrt[3]{2} - \sqrt[3]{2} = 13 \sqrt[3]{2}$

4)

a)

$\sqrt{5} . \sqrt{2} = \sqrt{5.2} = \sqrt{10}$

b)

$\sqrt[4]{2} . \sqrt[4]{8} = \sqrt[4]{2.8} = \sqrt[4]{16} = 2$

c)

$\sqrt{2} .( \sqrt{7} + 2) = \sqrt{2} . \sqrt{7} + \sqrt{2} .2 = \sqrt{14} + 2 \sqrt{2}$

5)

$( \sqrt{18} + \sqrt{98} + \sqrt{200} ) \div (2 \sqrt{2} + \sqrt{8} ) = ( \sqrt{9.2} + \sqrt{49.2} + \sqrt{100.2} ) \div (2 \sqrt{2} + \sqrt{4.2} ) = (3 \sqrt{2} + 7 \sqrt{2} + 10 \sqrt{2} ) \div (2 \sqrt{2} + 2 \sqrt{2} ) = (20 \sqrt{2}) \div (4 \sqrt{2} ) = \frac{20}{4} . \frac{ \sqrt{2} }{ \sqrt{2} } = 5.1 = 5$

b)

$(10 \sqrt{27} + 10 \sqrt{3} ) \div 10 \sqrt{3} = (10 \sqrt{9.3} + 10 \sqrt{3} ) \div 10 \sqrt{3} = (3.10 \sqrt{3} + 10 \sqrt{3} ) \div 10 \sqrt{3} = (30 \sqrt{3} + 10 \sqrt{3} ) \div 10 \sqrt{3} = 40 \sqrt{3} \div 10 \sqrt{3} = \frac{40}{10} . \frac{ \sqrt{3} }{ \sqrt{3} } = 4.1 = 4$

c)

$(20 \sqrt{10} + 10 \sqrt{18} ) \div 2 \sqrt{2} = (20 \sqrt{5.2} + 10 \sqrt{9.2} ) \div 2 \sqrt{2} = (20 \sqrt{5} . \sqrt{2} + 3.10 \sqrt{2} ) \div 2 \sqrt{2} = (20. \sqrt{5} . \sqrt{2} + 30 \sqrt{2} ) \div 2 \sqrt{2} = \frac{20 }{2}. \frac{ \sqrt{5}. \sqrt{2} }{ \sqrt{2} } + \frac{30}{2}. \frac{ \sqrt{2} }{ \sqrt{2} } = 10. \sqrt{5} + 15.1 = 15 + 10 \sqrt{5}$

6)

a)

$\frac{4}{7} . \sqrt{ \frac{49}{64} } + (1 - \frac{3}{5} ) \div \frac{3}{5} + (1 + \frac{1}{3} ) = \frac{4}{7} . \frac{7}{8} + ( \frac{5 - 3}{5} ) \div \frac{3}{5} + ( \frac{3 + 1}{3} ) = \frac{1}{2} + \frac{2}{5} \div \frac{3}{5} + \frac{4}{3} = \frac{1}{2} + \frac{2}{5} . \frac{5}{3} + \frac{4}{3} = \frac{1}{2} + \frac{2}{3} + \frac{4}{3} = \frac{3 + 4 + 8}{6} = \frac{15}{6} = \frac{5}{2}$

7)

a)

$( \sqrt{2} )^{2} = \sqrt{ {2}^{2} } = 2$

b)

$( \sqrt[3]{9} )^{2} = \sqrt[3]{ {9}^{2} } = \sqrt[3]{( {3}^{2})^{2} } = \sqrt[3]{ {3}^{4} } = \sqrt[3]{ {3}^{3}.3 } = 3 \sqrt[3]{3}$

c)

$(4 \sqrt{5} )^{3} + {4}^{3} . \sqrt{ {5}^{3} } = 64 \sqrt{ {5}^{2}.5 } = 5.64 \sqrt{5} = 320 \sqrt{5}$

d)

$( \sqrt{2} + \sqrt{3} )^{2} = ( \sqrt{2})^{2} + 2. \sqrt{2} . \sqrt{3} + ( \sqrt{3})^{2} = 2 + 2 \sqrt{6} + 3 = 5 + 2 \sqrt{6}$