Question

URGENTE!!!!
calcule o fatorial:

0! =
5! - 0! =

Simplifique:

a)$\frac{(n+2)!}{(n+1)!}$

b) $\frac{(n-3)!}{(n-2)!}$

Answer 1

0! = 1
5! - 0! = 5.4.3.2! - 1 = 20 . 6 - 1 = 120 - 1 = 119


a) $\frac{(n+2)!}{(n+1)!}$


$\frac{(n+2).(n+1)!}{(n+1)!}$

$\frac{(n+2).\not{(n+1)!}}{\not{(n+1)!}}$

$\boxed{\bold{(n + 2)}}$



b) $\frac{(n-3)!}{(n-2)!}$


$\frac{(n-3)!}{(n-2).(n-3)!}$

$\frac{\not{(n-3)!}}{(n-2).\not{(n-3)!}}$

$\boxed{\bold{\frac{1}{(n-2)}}}$