Question

URGENTE


Calcule a área dos paralelogramos

Answer 1

a) $S=bh$

$S=6\cdot3$

$S=18~\text{cm}^2$


b) $h^2+3^2=5^2$

$h^2+9=25$

$h^2=16$

$h=4~\text{m}$

$S=7\cdot4=28~\text{m}^2$.


c) $\text{tg}~60^{\circ}=\dfrac{h}{x}$

$\sqrt{3}=\dfrac{h}{x}$

$h=x\sqrt{3}$

$x^2+h^2=10^2$

$x^2+(x\sqrt{3})^2=100$

$x^2+3x^2=100$

$4x^2=100$

$x^2=25$

$x=5$

$h=5\sqrt{3}~\text{m}$.

$S=bh$

$S=18\cdot5\sqrt{3}=90\sqrt{3}~\text{m}^2$.


d) $\text{sen}~30^{\circ}=\dfrac{h}{6}$

$\dfrac{1}{2}=\dfrac{h}{6}$

$2h=6$

$h=3~\text{m}$

$S=bh$

$S=8\cdot3=24~\text{m}^2$.


e) $h^2+4^2=5^2$

$h^2+16=25$

$h^2=9$

$h=3~\text{cm}$

$S=bh$

$S=6\cdot3=18~\text{cm}^2$.


f) $x=20-b$

$x^2+8^2=10^2$

$x^2+64=100$

$x^2=36$

$x=6~\text{cm}$

$6=20-b$

$b=14~\text{cm}$

$S=bh$

$S=14\cdot8=112~\text{cm}^2$.