Question

up quem souber me ajuda agradeço desde já ​pfvvvv

Answer 1

Resposta:

Explicação passo-a-passo:

Função exponencial:

Vamos adotar 5 valores, unir os pontos e traçar o gráfico.

f(x)= 2^x

f(-2)= 2^(-2)= 1/4

f(-1)= 2^(-1)= 1/2

f(0)= 2^0= 1

f(1) = 2^1 = 2

f(2) = 2^2 = 4

x | y

-2 | 1/4

-1| 1/2

0 | 1

1 | 2

2 | 4

-----------

b)

f(x) = 3^x

f(-2)= 3^(-2) = (1/3)^2 = 1/9

f(-1)= 3^(-1) = 1/3

f(0)=3^0 = 1

f(1)= 3^1= 3

f(2)= 3^2= 9

x | y

-2 | 1/9

-1 | 1/3

0 | 1

1 | 3

2 | 9

-----------------

c)

f(x) = (1/2)^x

f(x)= (1/2)^x

f(-2) = (1/2)^(-2)

f(-2)= 2^2

f(-2) = 4

f(x) = (1/2)^x

f(-1)= (1/2)^(-1)

f(-1)= 2

x= 0

f(0)= (1/2)^0

y = 1

x = 1

f(x)= (1/2)^x

f(1)= (1/2)^1

y = 1/2

x = 2

f(2)= (1/2)^2 = 1/4

y = 1/4

x | y

-2 | 4

-1 | 2

0 | 1

1 | 1/2

2 | 1/4

---------------------

D)

f(x)= (1/4)^x

f(-2)= (1/4)^(-2)= 4^2 = 16

x= -1

f(x) = (1/4)^x

f(-1)= (1/4)^(-1)

f(-1) = 4^1

y = 4

x = 0

f(0)= (1/4)^0

y = 1

x = 1

f(x) = (1/4)^x

f(1) = 1/4^1 = 1/4

x = 2

f(2) = 1/4^2 = 1/16

-2 | 16

-1 | 4

0 | 1

1 | 1/4

2 | 1/16

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F(x) = 3^x

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