Question

Uma P.G de cinco termos onde a1= -3 e q=-5

Answer 1

Explicação passo-a-passo:

• $\sf a_1=-3$

• $\sf a_2=a_1\cdot q$

$\sf a_2=(-3)\cdot(-5)$

$\sf a_2=15$

• $\sf a_3=a_2\cdot q$

$\sf a_3=15\cdot(-5)$

$\sf a_3=-75$

• $\sf a_4=a_3\cdot q$

$\sf a_4=(-75)\cdot(-5)$

$\sf a_4=375$

• $\sf a_5=a_4\cdot q$

$\sf a_5=375\cdot(-5)$

$\sf a_5=-1875$

$\sf \red{PG(-3,15,-75,375,-1875)}$

Answer 2

Resposta:

P.G = ( - 3; 15 ; - 75 ; 375; - 1875)

Explicação passo-a-passo:

$a_{1} = - 3 \\ a_{2} = a_{1} \times q \\ a_{2} = ( - 3 )\times ( - 5) \\ a_{2} = 15 \\ a_{3} = a_{2} \times q \\ a_{3} = 15 \times ( - 5) \\ a_{3} = - 75 \\ a_{4} = a_{3} \times q \\ a_{4} = ( - 75) \times ( - 5) \\ a_{4} = 375 \\ a_{5} = a_{4} \times q \\ a_{5} = 375 \times ( - 5) \\ a_{5 } = - 1875$

P.G = ( - 3; 15 ; - 75 ; 375; - 1875)