Question

Uma mola de constante elástica 40 N/m sofre uma  deformação de 0,04 m calcule  a  energia potencial acumulada pela mola?

Answer 1

Epe = kx²/2

Epe = 40·(4·10⁻²)²/2
Epe = 20·16·10⁻⁴ = 320·10⁻⁴ 
Epe =0,032N ou  3,2·10⁻²N

Answer 2

$\Large{\begin{array}{l}\tt E_p=\dfrac{k\cdot x^2}{2}\\\\\tt E_p=\dfrac{40\cdot(0{,}04)^2}{2}\\\\\tt E_p=\dfrac{40\cdot0{,}0016}{2}\\\\\tt E_p=\dfrac{0{,}064}{2}\\\\\boxed{\boxed{\tt E_p=0{,}032\,J}}\end{array}}$