Question

Uma empresa libera, por dia, 13,2 toneladas de CO₂ ( gás carbônico) na atmosfera. Qual o volume de gás carbônico , nas CNTP, liberado por mês nessa empresa?                                                                                                                                                     (1 mês=30 dias) (1 Ton =10⁶ g)  Dado:  MA: C=12u, O=16u.

(a) 4,48 x 10⁸ L

(b) 6,72 x 10⁸ L

(c) 7,84 x 10⁸ L

(d) 3,36 x 10⁸ L

(e)2,02 x 10⁸ L

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Answer 1

$\Large\boxed{\begin{array}{l}\sf M_{CO_2}=12+2\cdot16=12+32=44g/mol\\\sf 44\,g\longrightarrow 22,4L\\\sf 10^6\,g\longrightarrow x\\\sf 44x=22,4\cdot10^6\\\sf x=\dfrac{22,4\cdot10^6}{44}\\\\\sf x=0,509\cdot10^6=5,09\cdot10^5\,L\\\sf 10^6\,g\longrightarrow 5,09\cdot10^5L\\\sf 13,2\cdot10^6\longrightarrow z\\\sf 10^6z=5,09\cdot10^5\cdot13,2\cdot10^6\\\\\sf z=\dfrac{5,09\cdot10^5\cdot13,2\cdot\diagup\!\!\!\!\!\!10^6}{\diagup\!\!\!\!\!10^6}\\\\\sf z=67,18\cdot10^5L=6,718\cdot10^6L\end{array}}$

$\Large\boxed{\begin{array}{l}\sf 1\,dia\longrightarrow6,718\cdot10^6\\\sf 30\,dias\longrightarrow y\\\sf y=30\cdot6,718\cdot10^6\\\sf y=201,54\cdot10^6\\\sf y=2,0154\cdot10^8L\\\sf y\approxeq2,02\cdot10^8L\\\huge\boxed{\boxed{\boxed{\boxed{\sf\maltese~alternativa~e}}}}\end{array}}$