Uma caixa papelao tem suas dimensoes 30 cm; x+10; x-4. A funçao V(x) que relaciona x com o vole da caixa e o respectivo volume para x=20 cm são:
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![V=a\times b \times c\\\\\\\
V(x)=30\times(x+10)\times(x-4)\\\\\\\
V(x)=30\times( x^{2} -4x+10x-40)\\\\\\\
V(x)=30\times( x^{2} +6x-40)\\\\\\\
V(x)=30 x^{2} +180x-1200](https://tex.z-dn.net/?f=V%3Da%5Ctimes+b+%5Ctimes+c%5C%5C%5C%5C%5C%5C%5C%0AV%28x%29%3D30%5Ctimes%28x%2B10%29%5Ctimes%28x-4%29%5C%5C%5C%5C%5C%5C%5C%0AV%28x%29%3D30%5Ctimes%28+x%5E%7B2%7D+-4x%2B10x-40%29%5C%5C%5C%5C%5C%5C%5C%0AV%28x%29%3D30%5Ctimes%28+x%5E%7B2%7D+%2B6x-40%29%5C%5C%5C%5C%5C%5C%5C%0AV%28x%29%3D30+x%5E%7B2%7D+%2B180x-1200 "V=a\times b \times c\\\\\\\
V(x)=30\times(x+10)\times(x-4)\\\\\\\
V(x)=30\times( x^{2} -4x+10x-40)\\\\\\\
V(x)=30\times( x^{2} +6x-40)\\\\\\\
V(x)=30 x^{2} +180x-1200")
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Solução!
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