Um xampu tem pH=8 . indique a H+ e OH-
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Devemos saber que ![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D "pH=-\log[H^+]")
. Logo, pelo valor dado:
![pH=-\log[H^+]\\\\
8=-\log[H^+]\\\\
\log[H^+]=8\\\\
\boxed{[H^+]=10^{-8}~mol/L}](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D%5C%5C%5C%5C%0A8%3D-%5Clog%5BH%5E%2B%5D%5C%5C%5C%5C%0A%5Clog%5BH%5E%2B%5D%3D8%5C%5C%5C%5C%0A%5Cboxed%7B%5BH%5E%2B%5D%3D10%5E%7B-8%7D%7Emol%2FL%7D "pH=-\log[H^+]\\\\
8=-\log[H^+]\\\\
\log[H^+]=8\\\\
\boxed{[H^+]=10^{-8}~mol/L}")
Além, disso, usando que![[H^+][OH^-]=10^{-14}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%5BOH%5E-%5D%3D10%5E%7B-14%7D "[H^+][OH^-]=10^{-14}")
:
![[H^+][OH^-]=10^{-14}\\\\
10^{-8}[OH^-]=10^{-14}\\\\~ [OH^-]=\dfrac{10^{-14}}{10^{-8}}\\\\
~[OH^-]=10^{-14-(-8)}\\\\
\boxed{[OH^-]=10^{-6}~mol/L}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%5BOH%5E-%5D%3D10%5E%7B-14%7D%5C%5C%5C%5C%0A10%5E%7B-8%7D%5BOH%5E-%5D%3D10%5E%7B-14%7D%5C%5C%5C%5C%7E+%5BOH%5E-%5D%3D%5Cdfrac%7B10%5E%7B-14%7D%7D%7B10%5E%7B-8%7D%7D%5C%5C%5C%5C%0A%7E%5BOH%5E-%5D%3D10%5E%7B-14-%28-8%29%7D%5C%5C%5C%5C%0A%5Cboxed%7B%5BOH%5E-%5D%3D10%5E%7B-6%7D%7Emol%2FL%7D "[H^+][OH^-]=10^{-14}\\\\
10^{-8}[OH^-]=10^{-14}\\\\~ [OH^-]=\dfrac{10^{-14}}{10^{-8}}\\\\
~[OH^-]=10^{-14-(-8)}\\\\
\boxed{[OH^-]=10^{-6}~mol/L}")
Além, disso, usando que
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