Question

um triangulo retangulo tem hipotenusa medindo x + 6 e os catetos x + 5 e x - 2 des cubra as medidas desse triângulo​

Answer 1

$> resolucao \\ \\ \geqslant teorema \: de \: pitagoras \\ \\ > a {}^{2} = b {}^{2} + c {}^{2} \\ \\ (x + 6) {}^{2} = (x + 5) {}^{2} + (x - 2) {}^{2} \\ {x}^{2} + 12x + 36 = {x}^{2} + 10x + 25 + {x}^{2} - 4x + 4 \\ 12x + 36 = {x}^{2} + 6x + 29 \\ {x}^{2} - 6x - 7 = 0 \\ (x + 1)(x - 7) = 0 \\ \\ x + 1 = 0 \\ x = - 1 \\ \\ x - 7 = 0 \\ x = 7 \\ \\ > as \: medidas \: do \: triangulo \\ \\ \\ > x + 6 > 7 + 6 = 13 \\ > x + 5 > 7 + 5 = 12 \\ > x - 2 > 7 - 2 > 5 \\ \\ \\ resposta \: > \: 13 \: \: . \: \: 12 \: \: e \: \: 5 \\ \\ > < > < > < > < >$