um polígono regular com exatamente 35 diagonais tem:
a)6lados
b)10blados
c)20lados
d)9lados
e)12lados
Soluções para a tarefa
Resposta:b)10blados
Explicação passo-a-passo:
a)n=6,p=2
Cn,p=n!/(n-p)!p! dn=Cn,p-n dn=n.(n-3)/2
C6,2=6!/(6-2)!2! d6=15-6 ou d6=6.(6-3)/2
C6,2=8!/4!.2! d6=9 d6=6.3/2
C6,2=6.5.4!/4!.2 d6=3.3
C6,2=30/2 d6=9
C6,2=15
b)n=10,p=2
Cn,p=n!/(n-p)!p! dn=Cn,p-n dn=n.(n-3)/2
C10,2=10!/(10-2)!2! d10=45-10 ou d10=10.(10-3)/2
C10,2=10!/8!.2! d15=35 d10=10.7/2
C10,2=10.9.8!/8!.2 d10=15.7
C10,2=90/2 d10=35
C10,2=45
c)n=20,p=2
Cn,p=n!/(n-p)!p! dn=Cn,p-n dn=n.(n-3)/2
C20,2=20!/(20-2)!2! d20=190-20 ou d20=20.(20-3)/2
C20,2=20!/18!.2! d20=170 d20=20.17/2
C20,2=20.19.18!/18!.2 d20=10.17
C20,2=380/2 d20=170
C20,2=190
d)n=9,p=2
Cn,p=n!/(n-p)!p! dn=Cn,p-n dn=n.(n-3)/2
C9,2=9!/(9-2)!2! d9=36-9 ou d9=9.(9-3)/2
C9,2=9!/7!.2! d9=27 d9=9.6/2
C9,2=9.8.7!/7!.2 d9=9.3
C9,2=72/2 d9=27
C9,2=36
e)n=12,p=2
Cn,p=n!/(n-p)!p! dn=Cn,p-n dn=n.(n-3)/2
C12,2=12!/(12-2)!2! d12=66-12 ou d12=12.(12-3)/2
C12,2=12!/10!.2! d12=54 d12=12.9/2
C12,2=12.11.10!/10!.2 d12=6.9
C12,2=132/2 d12=54
C12,2=66