Um pedestre percorre, inicialmente, 4/9 de uma avenida. Em seguida, percorre mais 1/3 da mesma avenida, e ficam faltando 200 metros para ele chegar ao final dela. Qual é a medida do comprimento da avenida?
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Bom dia!
Solução!
Comprimento total da avenida=x
![\dfrac{4x}{9}+ \dfrac{1x}{3}+200=x \\\\\\
MMC~(9,3)=9\\\\\\
Fazendo!\\\\\\
4x+3x+1800=9x\\\\\
7x+1800=9x\\\\\\
7x-9x=-1800\\\\\\
-2x=-1800\\\\\\\
x= \dfrac{-1800}{-2}\\\\\\\
x=900](https://tex.z-dn.net/?f=+%5Cdfrac%7B4x%7D%7B9%7D%2B+%5Cdfrac%7B1x%7D%7B3%7D%2B200%3Dx+%5C%5C%5C%5C%5C%5C%0AMMC%7E%289%2C3%29%3D9%5C%5C%5C%5C%5C%5C%0AFazendo%21%5C%5C%5C%5C%5C%5C%0A4x%2B3x%2B1800%3D9x%5C%5C%5C%5C%5C%0A7x%2B1800%3D9x%5C%5C%5C%5C%5C%5C%0A7x-9x%3D-1800%5C%5C%5C%5C%5C%5C%0A-2x%3D-1800%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-1800%7D%7B-2%7D%5C%5C%5C%5C%5C%5C%5C%0Ax%3D900++ "\dfrac{4x}{9}+ \dfrac{1x}{3}+200=x \\\\\\
MMC~(9,3)=9\\\\\\
Fazendo!\\\\\\
4x+3x+1800=9x\\\\\
7x+1800=9x\\\\\\
7x-9x=-1800\\\\\\
-2x=-1800\\\\\\\
x= \dfrac{-1800}{-2}\\\\\\\
x=900")
Bom dia!
Bons estudos!
Solução!
Comprimento total da avenida=x
Bom dia!
Bons estudos!
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