Question

Um motociclista de massa 60 kg está montando em sua motocicleta de 200 kg enquanto trafega 54 km/h (15m/s. Qual a energia cinética associada ao movimento desse motociclista e seu veículo?

Answer 1

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⠀⠀⠀☞ 29,25 [KJ]. ✅

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⠀⠀⠀⭐⠀Para realizar este exercício vamos rever o conceito de energia cinética.⠀⭐⠀

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⠀⠀⠀☔⠀Oi, Regina ✌. Lembrando que a energia cinética equivale ao trabalho (ou seja, a energia necessária) da força que varia a velocidade do corpo do repouso (0 m/s) até a velocidade atual então temos que:

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                        $\Large\gray{\boxed{\sf\orange{~~\begin{array}{lcr}&&\\&\pink{\text{\huge \underline{~~\bf Energia~~} }}\\&\pink{\text{\huge \underline{~~\bf Cin\acute{e}tica~~} }}&\\\\\\&\orange{\sf E_{cin} = \tau_{_F} = F \cdot d}&\\\\\\&\green{\clubsuit\underline{~\sf ~Pela~2^{a}~lei~de~Newton:~}\clubsuit}&\\\\&\orange{\sf E_{cin} = m \cdot a \cdot d}&\\\\\\&\green{\clubsuit\underline{~\sf ~Pela~eq.~de~Torricelli:~}\clubsuit}&\\\\&\orange{\sf E_{cin} = m \cdot \dfrac{v_f^2 - v_0^2}{2}}&\\\\\\&\green{\clubsuit\underline{~\sf ~Para~v_{_0} = 0~temos:~}\clubsuit}&\\\\\\&\red{\boxed{\LARGE\pink{\boxed{\begin{array}{lcr}\green{\star}&&\green{\star}\\&\!\!\orange{\bf E_{cin} = \dfrac{m \cdot v^2}{2}}\!\!&\\\green{\star}&&\green{\star}\\\end{array}}}}}&\\&&\end{array}~~}}}$  

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⌚ Hora da matemágica ✍

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                              $\Large\gray{\boxed{\sf~~\begin{array}{c}~\\\pink{\underline{~\underline{\text{\LARGE \bf\square\!\!\boxed{\subset}\boxed{\emptyset}\boxed{\eta}\boxed{\pi}\!\!\!^{^{\square}}\boxed{\alpha}\boxed{\ }\!_{\square} }}~}}\\\\\\\blue{\begin{cases}\sf~v = 15~[m/s]\\ \sf~m = 260~[Kg]\\ \sf~E_{cin}=~?~[J]\end{cases}}\\\\\!\!\!\!\!\!\!\!^{\underline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\!\!\!\!\!\!\!\!\\\orange{\LARGE\bf E_{cin} = \dfrac{m \cdot v^2}{2}}\\\!\!\!\!\!\!\!\!^{\underline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\!\!\!\!\!\!\!\!\\\blue{\sf E_{cin} = \dfrac{260 \cdot 15^2}{2}}\\\!\!\!\!\!\!\!\!^{\underline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\!\!\!\!\!\!\!\!\\\blue{\sf E_{cin} = 130 \cdot 225}\\\!\!\!\!\!\!\!\!^{\underline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\!\!\!\!\!\!\!\!\\\\\green{\boxed{\blue{\sf~E_{cin} = 29.250~[J]}}~\checkmark}\\\\\end{array}~~}}$

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                             $\bf\large\red{\underline{\quad\quad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}$☁

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⠀⠀⠀☀️ L͎̙͖͉̥̳͖̭̟͊̀̏͒͑̓͊͗̋̈́ͅeia mais sobre energia cinética:

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                                     https://brainly.com.br/tarefa/49353262 ✈  

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                                     $\huge\blue{\text{\bf\quad Bons~estudos.}}$ ☕

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                                          $\quad\qquad(\orange{D\acute{u}vidas\ nos\ coment\acute{a}rios})$ ☄

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                             $\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad }\LaTeX}$✍

                                $\sf(\purple{+}~\red{cores}~\blue{com}~\pink{o}~\orange{App}~\green{Brainly}$ ☘☀❄☃☂☻)

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                                                          $\Huge\green{\text{ \underline{\red{\mathbb{S}}\blue{\mathfrak{oli}}~}~\underline{\red{\mathbb{D}}\blue{\mathfrak{eo}}~}~\underline{\red{\mathbb{G}}\blue{\mathfrak{loria}}~} }}$ ✞

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