Um menino e seu cao, juntos, tem 58 kg. Se o menino tem 26 kg a mais do que o cao, quantos kg tem o cao
Soluções para a tarefa
Respondido por
8
58-26=32 32/2=16 , na forma que eu aprendi daria esse resultado
Respondido por
3
Boa tarde!
Solução!
![M+C=58\\\\
m=C+26\\\\\\
C+26+C=58\\\\\
2C=58-26\\\\\
2C=32\\\\\
C= \frac{32}{2}\\\\\\
\boxed{C=16Kg}\\\\\\\\\
M+C=58\\\\
M+16=58\\\\
M=58-16\\\\\\
\boxed{M=42Kg}](https://tex.z-dn.net/?f=M%2BC%3D58%5C%5C%5C%5C%0Am%3DC%2B26%5C%5C%5C%5C%5C%5C%0AC%2B26%2BC%3D58%5C%5C%5C%5C%5C%0A2C%3D58-26%5C%5C%5C%5C%5C%0A2C%3D32%5C%5C%5C%5C%5C%0AC%3D+%5Cfrac%7B32%7D%7B2%7D%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BC%3D16Kg%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A+M%2BC%3D58%5C%5C%5C%5C%0AM%2B16%3D58%5C%5C%5C%5C%0AM%3D58-16%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BM%3D42Kg%7D "M+C=58\\\\
m=C+26\\\\\\
C+26+C=58\\\\\
2C=58-26\\\\\
2C=32\\\\\
C= \frac{32}{2}\\\\\\
\boxed{C=16Kg}\\\\\\\\\
M+C=58\\\\
M+16=58\\\\
M=58-16\\\\\\
\boxed{M=42Kg}")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
Perguntas interessantes
Português,
9 meses atrás
Geografia,
9 meses atrás
Geografia,
9 meses atrás
Matemática,
1 ano atrás
Matemática,
1 ano atrás