Question

Um exercício de Integral em anexo abaixo:

Answer 1

$\int (x+3)*(2x-1)dx\\\\\int (2x^2-x+6x-3)dx\\\\ \boxed{\boxed{\int(2x^2+5x-3)dx= \frac{2x^3}{3} + \frac{5x^2}{2} - 3x + C }}$

Answer 2

$\int\limits {(x+3)(2x-1)} \, dx = \int\limits {(2x^{2}+6x-x+3)} \, dx \\ \\ 2 \int\limits {x^{2}} \, dx - \int\limits {x} \, dx +6 \int\limits {x} \, dx - \int\limits {3} \, dx \\ \\ \frac{2x^{3}}{3} - \frac{x^{2}}{2} + \frac{6x^{2}}{2} -3x = \\ \\ \frac{2x^{3}}{3} - \frac{x^{2}}{2} + 3x^{2} -3x+C$