Question

Um capital de 51.879 .31 centavos aplicado por 6 meses resultou em r$ 120000 qual a taxa efetiva ganha

Answer 1

 Usando a formula M=C(1+i*t)

120000=51879,31(1+i*6)
120000/51879,31=1+i*6
2,313=1+i*6
2,313-1=i*6
1,313=i*6
i=1,313/6
i=0,218
i=0,218*100
i=21,8% a.m.

Answer 2

Bom Dia!

Dados; Juros composto:

C → 51879,31

t → 6

M → 120000

i → ?

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M=c·(i+1)^t

120000=51879,31·(i+1)⁶

120000/51879,31=(i+1)⁶

2,3=(i+1)⁶

⁶√2,313=i+1

1,149=i+1

1,149-1=i

i=0,149

i=0,149×100

i=14,9

i≅15%a.m ( resposta para juros compostos)

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Dados; juros simples:

C → 51879,31

t → 6

M → 120000

i → ?

J → ?

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Em busca do juros:

M=C+J

120000= 51879,31+J

120000-51879,31=J

J=R$68.120,69

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Em busca da taxa:

J=c·i·t

68.120,69=51879,31·i·6

68.120,69/51879,31=i·6

1,313=i·6

1,313/6=i

i=0,218

i=0,218×100

i=21,8

i≅22%a.m (resposta para juros simples)

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Att;Guilherme lima