Question

um capital 51.879,31 aplicado por 6 meses resultou em 120.000,00.Qual a taxa efetiva ganha?

Answer 1

i=j*100/C/t

i=120000-51879,31*100/51879,31

i=68120,69*100/51879,31/6

i=6812069/51879,31/6

i=131,30.../6

i=21,88...

Resposta: Taxa de 21,88%a.m. (aproximadamente)

Answer 2

Bom Dia!

Dados; Juros composto:

C → 51879,31

t → 6

M → 120000

i → ?

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M=c·(i+1)^t

120000=51879,31·(i+1)⁶

120000/51879,31=(i+1)⁶

2,3=(i+1)⁶

⁶√2,313=i+1

1,149=i+1

1,149-1=i

i=0,149

i=0,149×100

i=14,9

i≅15%a.m ( resposta para juros compostos)

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Dados; juros simples:

C → 51879,31

t → 6

M → 120000

i → ?

J → ?

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Em busca do juros:

M=C+J

120000= 51879,31+J

120000-51879,31=J

J=R$68.120,69

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Em busca da taxa:

J=c·i·t

68.120,69=51879,31·i·6

68.120,69/51879,31=i·6

1,313=i·6

1,313/6=i

i=0,218

i=0,218×100

i=21,8

i≅22%a.m (resposta para juros simples)

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Att;Guilherme lima