Question

Um capacitor de 285 μF é carregado a 220 Volts. Quanta energia foi armazenada nesse capacitor?

Answer 1

$C=285\ \mu F=285\times10^{-6}\ F=2.85\times10^{-4}\ F$

$U=220\ V$

$\boxed{E=\dfrac{1}{2}CU^2}\ \to\ E=\dfrac{1}{2}(2.85\times10^{-4})(2.2\times10^2)^2\ \to$

$E=1.425\times4.84\times10^{-4}\times10^4\ \to\ \boxed{E=6.897\ J}$