Question

(UFMG/99) Como se resolve?​

Answer 1

$m=\dfrac{7-2^2\left(1-\dfrac{4}{3}\right)}{1+\dfrac{1}{4}}\quad\mbox{tirando o mmc no pareseteses e no denomiador e resolvendo a potencia}\\\\m=\dfrac{7-4\left(\dfrac{3-4}{3}\right)}{\dfrac{4+1}{4}}\\\\m=\dfrac{7-4\left(\dfrac{-1}{3}\right)}{\dfrac{5}{4}}\\\\m=\dfrac{7+\dfrac{4}{3}}{\dfrac{5}{4}}\quad\mbox{tirando o mmc no numerador}\\\\m=\dfrac{\dfrac{21+4}{3}}{\dfrac{5}{4}}\\\\m=\dfrac{\dfrac{25}{3}}{\dfrac{5}{4}}\quad\mbox{realizando agora a divisao de fracao}$$m=\dfrac{25}{3}\cdot\dfrac{4}{5}\quad\mbox{simplificando o 5 com o 25}\\\\m=\dfrac{5}{3}\cdot4\\\\\boxed{\boxed{m=\dfrac{20}{3}}}$

Letra D