Question

(UFJF - MG) As raízes da equação
x² - 8x + 12=0 são: com os calculos pff

Answer 1

$x^2 - 8x + 12=0 \\ a = 1, b = -8, c = 12 \\ \\ \Delta = b^2 - 4ac \\ \Delta = (-8)^2 - 4 \times 1 \times 12 \\ \Delta = 64 - 48 \\ \Delta = 16 \\ \\ x = \frac{-b \pm \sqrt{\Delta}}{2a} \\ x = \frac{-(-8) \pm \sqrt{16}}{2 \times 1} \\ x = \frac{8 \pm 4}{2} \\ \\ x_1 = \frac{8 + 4}{2} = \frac{12}{2} = 6 \\ x_2 = \frac{8 - 4}{2} = \frac{4}{2} = 2 \\ \\ S = \{6, 2\}$