Question

UF-ES- a equaçao x²-10x+25 = 0   tem as seguintes soluçoes no conjunto dos numeros reais ;

Answer 1

Resolução pela fórmula de Bhaskara, veja:

$x^{2}-10x+25=0\\\\\\\ x = -b~\pm~\dfrac{ \sqrt{b^{2}-4~.~a~.~c}}{2~.~a}}\\\\\\ x = 10~\pm~\dfrac{ \sqrt{(-10)^{2}-4~.~1~.~25}}{2~.1}}\\\\\\\ x = 10~\pm~\dfrac{ \sqrt{100-100}}{2}}\\\\\\\ x = 10~\pm~\dfrac{ \sqrt{0}}{2}}\\\\\\ Quando~\Delta = 0,~x'=x''\\\\\\ x'=x'' = \dfrac{10}{2}}\\\\\\ \large\boxed{\boxed{x'=x''=5.}}$

Espero que te ajude :).