Question

(uel-pr) logx na base 2 + logx na base 4 + logx na base 16 = - 6.25

Answer 1

Passando todos os log para base 2 teremos:
$log_2x+\frac{1}{2} log_2x+\frac{1}{4} log_2x=-6,25$
$\frac{7}{4} log_2x=-6,25 log_2x=-25/7$
$x=2^{-25/7}$
$x = \frac{ \sqrt[7]{8} }{16}$