Question

U=Q(x+2)+(x+3)+(x+4)≤1

Answer 1

(x+2)+(x+3)+(x+4)≤1

3x+9 ≤ 1

3x ≤ -8

x ≤ -8/3

Answer 2

Resposta:

$(x + 2) + (x + 3) + (x + 4) \leqslant 1 \\ x + 2 + x + 3 + x + 4 \leqslant 1 \\ x + x + x \leqslant 1 - 2 - 3 - 4 \\ 3x \leqslant - 8 \\ x \leqslant - \frac{8}{3}$