Question

U = Q
7(x + 4) < 5 + 6(x + 2)

Answer 1

Resposta:

Explicação passo-a-passo:

$7(x+4)<5+6(x+2)\\\\7x+28<5+6x+12\\\\7x-6x<5+12-28\\\\x<-11\qquad x\in (-\infty; -11)$

Answer 2

Resposta:

7(x+4)<5+6(x+2)

7x+28<5+6x+12

7x-6x<5+12-28

x<17-28

x<-11

espero te ajudar!