Question

trinomio quadrado perfeito x2+12x+36=0

Answer 1

d=b2-4ac
d=144-4.1.36=0

x=-b+-rzd/2a
x1=x2=-12/2=-6

Answer 2

x² + 12x + 36 = 0 

a = 1
b=12
c = 36

Δ =b² - 4ac
Δ =12² - 4.1.36
Δ = 144 - 144
Δ = 0


-b ±√Δ / 2a
- 12 ±√0 / 2.1
-12 ± 0 / 2

x' = -12 + 0 /2
x'= -12/2
x'= -6

x" = -12 - 0 / 2 
x" = -12 / 2 
x" = -6


S = { - 6 }


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Gannicus
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