Question

Triangulo retângulo hip 2√5/5 cateto oposto 8√5/25 cateto adjacente X
Qual o valor do angulo Beta?

Answer 1

senB= b/a

senB= 8√5/25 / 2√5/5

senB= 8√5/25 × 5/2√5

senB= 40√5 / 50√5

senB = 4/5 ==> B= sen-¹(4/5) ≈ 53° 7'