Question

transforme os numeros mistos em fraçao improprias me ajudem por favor ​

Answer 1

Explicação passo-a-passo:

a)

$\sf 3~\dfrac{1}{3}=\dfrac{3\cdot3+1}{3}=\dfrac{9+1}{3}=\red{\dfrac{10}{3}}$

b)

$\sf 2~\dfrac{4}{5}=\dfrac{2\cdot5+4}{5}=\dfrac{10+4}{5}=\red{\dfrac{14}{5}}$

c)

$\sf 3~\dfrac{2}{3}=\dfrac{3\cdot3+2}{3}=\dfrac{9+2}{3}=\red{\dfrac{11}{3}}$

d)

$\sf 6~\dfrac{3}{4}=\dfrac{6\cdot4+3}{4}=\dfrac{24+3}{4}=\red{\dfrac{27}{4}}$

e)

$\sf 3~\dfrac{5}{7}=\dfrac{3\cdot7+5}{7}=\dfrac{21+5}{7}=\red{\dfrac{26}{7}}$

f)

$\sf 6~\dfrac{4}{5}=\dfrac{6\cdot5+4}{5}\dfrac{30+4}{5}=\red{\dfrac{34}{5}}$