Question

transforme numa única potência ?

A-
$5 {}^{7} \times 5 {}^{2} =$
B-
$a \times a {}^{4} =$
C-
$7 \times {7}^{3} \times 49 =$
D-
${7}^{10} \div {7}^{4 = }$
E-
${3}^{2} \div {3}^{ - 5 } =$
F-
${10}^{6} \div {10}^{3} \div 10 =$
me ajudem por favor..​

Answer 1

a) 5^7× 5²= 5^9

b)a×a⁴= a^5

c)7×7³×7²= 7^6

d)7^10÷7⁴= 7^6

e)3²÷3^-5= 3^²-(-5)= 3^ 2+5=3^7

f)10^6÷10³÷10= 10^6-3-1= 10²

Answer 2

Olá, utilizando as propriedades da potenciação temos que:

${5}^{7}\times{5}^{2}={5}^{7 + 2} =5^{9}\\\\a \times {a}^{4} = {a}^{4 + 1}={a}^{5}\\\\7 \times {7}^{3}\times 49=\\7 \times{7}^{3}\times{7}^{2}=\\ {7}^{1 + 3 + 2}= \\{7}^{6}\\\\7^{10} /7^4=7^{10-4}=7^6\\\\{3}^{2} \div {3}^{ - 5}={3}^{2 - -5}={3}^{7}\\\\{10}^{6}\div{10}^{3} \div 10=\\{10}^{6 - 3 - 1}=\\{10}^{2}$