Question

transforme em fraçaõ irredutivel a)1,666... b) 1,25 c) 0,5333...

Answer 1

a)
$x=1,666...\\ \\ x=1+0,666...\\ \\ x=1+\frac{6}{9}\\ \\ x=1+\frac{2}{3}=\frac{5}{3}$

b)
$x=1,25\\ \\ x=\frac{125}{100}=\frac{5}{4}$

c)
$x=0,5333...\\ \\ 10x=5,333...\\ \\ 10x=5+0,333...\\ \\ 10x=5+\frac{3}{9}\\ \\ 10x=\frac{48}{9}\\ \\ x=\frac{48}{90}=\frac{8}{15}$